LeetCode 1051 height Checker C++

Easy

---

A school is trying to take an annual photo of all the students. The students are asked to stand in a single file line in non-decreasing order by height. Let this ordering be represented by the integer array expected where expected[i] is the expected height of the ith student in line.

You are given an integer array heights representing the current order that the students are standing in. Each heights[i] is the height of the ith student in line (0-indexed).

Return the number of indices where heights[i] != expected[i].

 

Example 1:

Input: heights = [1,1,4,2,1,3]
Output: 3
Explanation: 
heights:  [1,1,4,2,1,3]
expected: [1,1,1,2,3,4]
Indices 2, 4, and 5 do not match.

Example 2:

Input: heights = [5,1,2,3,4]
Output: 5
Explanation:
heights:  [5,1,2,3,4]
expected: [1,2,3,4,5]
All indices do not match.

Example 3:

Input: heights = [1,2,3,4,5]
Output: 0
Explanation:
heights:  [1,2,3,4,5]
expected: [1,2,3,4,5]
All indices match.

 

Constraints:

• 1 <= heights.length <= 100
• 1 <= heights[i] <= 100

https://leetcode.com/problems/height-checker/

Height Checker - LeetCode

class Solution {
public:
    int heightChecker(vector<int>& heights) {
        vector<int> ans = heights;
        int idx = 0;
        sort(ans.begin(), ans.end());
        for(int i = 0; i < heights.size(); i++)
        {
            if(heights[i] != ans[i])
            {
                idx++;
            }
        }
        return idx;
    }
};